Nam H. Pham

 
#include <iostream>
using namespace std;
 
bool isLeapYear(int year){
	return (year % 4 == 0 && year%100 != 0 || year%400 == 0);
}
int main(){
	int cDay = 24,cMonth = 3,cYear = 2010,cWeekDay = 4-2;
	int fDay = 1,fMonth = 1,fYear = 2011,fWeekDay = 0;
	int months[] = {31,28,31,30,31,30,31,31,30,31,30,31};
	char* weekDays[] = {"Monday","Tuesday","Wednesday","Thursday","Friday","Saturday","Sunday"};
	int cLeft = 0, fLeft = 0, totalDays = 0;
 
	//calculate the days left for current
	if (isLeapYear(cYear)) months[1] = 29;
	else months[1] = 28;
	cLeft = -cDay;
	for (int i = cMonth;i <= 11;i++)
		cLeft += months[i-1];
 
	//calculate the days left for future
	if (isLeapYear(fYear)) months[1] = 29;
	else months[1] = 28;
	fLeft = -fDay;
	for (int i = fMonth;i <= 11; i++)
		fLeft += months[i-1];
 
	//calculate the days between two years
	for (int year = cYear+1;year <= fYear;year ++) // <= fYear is important key !!!
		if (isLeapYear(year))
			totalDays += 366;
		else totalDays += 365;
 
	totalDays += cLeft - fLeft; // final formular
 
	fWeekDay = (cWeekDay + totalDays) % 7;
 
	cout << "Future WeekDay is " << weekDays[fWeekDay] << endl;
 
	system("pause");	
	return 0;
}

//input: a String, convert it to array. 
//output: return formated String
        public String removeBlanks(String str){
		int strLength = str.length();
		char[] seq = new char[strLength+1];
		int length = -1;
		for (int i = 0; i < strLength; i++)
			if (str.charAt(i) != ' ' || (length >= 0 && seq[length] != ' '))
				seq[++length] = str.charAt(i);
 
		if (length == -1) return ""; // empty string
 
		if (seq[length] != ' ') 
			return new String(seq,0,length+1);
		else //remove trailing blank
			return new String(seq,0,length);
	}